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8m^2+8m-96=0
a = 8; b = 8; c = -96;
Δ = b2-4ac
Δ = 82-4·8·(-96)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-56}{2*8}=\frac{-64}{16} =-4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+56}{2*8}=\frac{48}{16} =3 $
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